Regular expression to get text between last brackets ()

Question

I want to extract text between the last ()using javascript

for instance

var someText="don't extract(value_a) but extract(value_b)";
alert(someText.match(regex));

The result should be

value_b

thanks for the help

+5

user1376366 May 05 '12 at 6:23

4 answers

/\([^()]+\)(?=[^()]*$)/

Appearance (?=[^()]*$)states that there are more parentheses before the end of input.

+5

Alan moore May 05 '12 at 6:34

var str = "don't extract(value_a) but extract(value_b)";

var res = str.match(/.*\(([^)]+)\)/)[1];

console.log(res);

+2

bobble bubble Aug 19 '17 at 23:30

If the last closing bracket is always at the end of the sentence, you can use Jonathans answer. Otherwise, this might work:

/\((\w+)\)(?:(?!\(\w+\)).)*$/

0

Avaq May 05 '12 at 6:37

stema · Accepted Answer · 2012-05-05T06:38:15+0000

try it

\(([^)]*)\)[^(]*$

var someText="don't extract(value_a) but extract(value_b)";
alert(someText.match(/\(([^)]*)\)[^(]*$/)[1]);

The part inside the brackets is stored in capture group 1, so you need to use it match()[1]to access the result.