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Sort dicts list by dict values

I have the following list of dictionaries

a = [{23:100}, {3:103}, {2:102}, {36:103}, {43:123}]

How can I sort it:

a = [{43:123}, {3:103}, {36:103}, {2:102}, {23:100}]

I mean, sort the list by its dicts values, in descending order.

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4 answers

In addition to answering brandies, you can go with:

sorted(a, key=dict.values, reverse=True)

Pretty much the same, but perhaps more idiomatic.

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>>> sorted(a, key=lambda i: i.values()[0], reverse=True)
[{43: 123}, {3: 103}, {36: 103}, {2: 102}, {23: 100}]
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key list.sort(), key:

>>> a = [{23:100}, {3:103}, {2:102}, {36:103}, {43:123}]
>>> a.sort(key=lambda d: d.values()[0], reversed=True)
>>> a
[{23: 100}, {2: 102}, {3: 103}, {36: 103}, {43: 123}]

- , d .values(). , . list.sort() , , .

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I would prefer to use (or at least remember) .itervalues()

In [25]: sorted(a, key=lambda x: x.itervalues().next, reverse=True)
Out[25]: [{43: 123}, {36: 103}, {2: 102}, {23: 100}, {3: 103}]
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