Complete conversion char [] & # 8594; halfway through the null pointer

I am trying to replicate this in Java. To save your click, it says that the character-to-character ['F', 'R', 'A', 'N', 'K', NULL, 'k', 'e', 'f', 'w']when it is converted to a zero-terminated string will stop afterwards 'K', since there is a null pointer there. However, my Java attempts do not seem to work.

public class TerminatingStrings{
    public static void main(String[] args){
        char[] broken = new char[3];
        broken[0] = 'a';
        broken[1] = '\u0000';
        broken[2] = 'c';
        String s = new String(broken);
        System.out.println(s);
    }
}

Prints ac. Besides this, I also tried (1) not to initialize broken[1]and (2), explicitly setting it to null, in an attempt that did not even compile.

Is this even possible in Java? Or maybe my understanding of things is wrong?