So, I am writing a game in C ++ for MS-DOS, and I include some built-in assemblies for speed. This particular block of code would draw a star in the video memory (0A000h). The problem with my code is that it only draws one pixel in any dh color. As far as I know mov dx, 00007h is equivalent to setting dh to 0 and dl to 7. What is wrong?
The equivalent C / C ++ code (or at least my intention) next to each line is indicated. My compiler is turbo C ++ 3.0. I am trying to use only instructions 8086/8088.
I also know how old MS-DOS doesnβt tell me to write code for a newer compiler / operating system. Writing code for dos is a kind of hobby.
pixelOffset = x + (y << 6) + (y << 8);
_asm {
mov ax, WORD PTR pixelOffset
mov di, ax
mov ax, 0A000h ;pointer to the video memory
mov es, ax
mov dx, 00007h ;indexed color 00 and 07
mov cx, 0000Fh ;indexed color white 0F
add ax, 2 ;pixelOffset += 2;
mov es:[di], dh ;videomem[pixelOffset] = BLACK;
add ax, 319 ;pixelOffset += 319;
mov es:[di], dh ;videomem[pixelOffset] = BLACK;
add ax, 1 ;pixelOffset += 1;
mov es:[di], dl ;videomem[pixelOffset] = LIGHT_GRAY;
add ax, 1 ;pixelOffset += 1;
mov es:[di], dh ;videomem[pixelOffset] = BLACK;
add ax, 317 ;pixelOffset += 317;
mov es:[di], dh ;videomem[pixelOffset] = BLACK;
add ax, 1 ;pixelOffset += 1;
mov es:[di], dl ;videomem[pixelOffset] = LIGHT_GRAY;
add ax, 1 ;pixelOffset += 1;
mov es:[di], cx ;videomem[pixelOffset] = WHITE;
add ax, 1 ;pixelOffset += 1;
mov es:[di], dl ;videomem[pixelOffset] = LIGHT_GRAY;
add ax, 1 ;pixelOffset += 1;
mov es:[di], dh ;videomem[pixelOffset] = BLACK;
add ax, 317 ;pixelOffset += 317;
mov es:[di], dh ;videomem[pixelOffset] = BLACK;
add ax, 1 ;pixelOffset += 1;
mov es:[di], dl ;videomem[pixelOffset] = LIGHT_GRAY;
add ax, 1 ;pixelOffset += 1;
mov es:[di], dh ;videomem[pixelOffset] = BLACK;
add ax, 319 ;pixelOffset += 319;
mov es:[di], dh ;videomem[pixelOffset] = BLACK;
}