Is it possible to update items in a list (structure)?

If I accumulate data without prior information about the number of elements, I can use the array and increase it with if necessary Redim Preserve, but the List will usually be more efficient. For instance:

Dim vehicle As New List(Of String)(4)

vehicle.Add("car")
vehicle.Add("bicycle")
vehicle.Add("truck")
vehicle.Add("taxi")
vehicle.Add("motorbike")
vehicle.Add("bus")

Although my assumption of 4 as the maximum number of elements was incorrect, I can add new elements without problems.

I can display elements like this:

For inx = 0 To vehicle.Count - 1
    Debug.Print("    " & inx & " " & vehicle(inx))
Next

and get:

0 car
1 bicycle
2 truck
3 taxi
4 motorbike
5 bus

I can update items as needed and re-render:

vehicle(2) = "coach"
vehicle(4) = "cart"

For inx = 0 To vehicle.Count - 1
    Debug.Print("    " & inx & " " & vehicle(inx))
Next

To obtain:

0 car
1 bicycle
2 coach
3 taxi
4 cart
5 bus

I can create a list of structures almost as easily:

Structure SpersonDtl
    Dim familyName As String
    Dim givenName As String
    Dim age As Integer
End Structure

Dim personDtl As New List(Of SpersonDtl)(4)
Dim personDtlCrnt As SpersonDtl

personDtlCrnt.familyName = "Smith"
personDtlCrnt.givenName = "John"
personDtlCrnt.age = 20
personDtl.Add(personDtlCrnt)

personDtlCrnt.familyName = "Brown"
personDtlCrnt.givenName = "Clare"
personDtlCrnt.age = 21
personDtl.Add(personDtlCrnt)

personDtlCrnt.familyName = "Wilson"
personDtlCrnt.givenName = "David"
personDtlCrnt.age = 22
personDtl.Add(personDtlCrnt)

personDtlCrnt.familyName = "Fox"
personDtlCrnt.givenName = "Wendy"
personDtlCrnt.age = 23
personDtl.Add(personDtlCrnt)

Display list contents with:

For inx = 0 To personDtl.Count - 1
    Debug.Print("    " & inx & " " & personDtl(inx).givenName & " " & _
                personDtl(inx).familyName & " " & personDtl(inx).age)
Next

gives:

0 John Smith 20
1 Clare Brown 21
2 David Wilson 22
3 Wendy Fox 23

If personDtl was an array, I could easily update the element. To fix Wendy's age, I would write:

personDtl(3).age = 24

personDtl(3).age : " , , ".

, :

Dim personDtlCrnt As SpersonDtl

personDtlCrnt = personDtl(3)
personDtlCrnt.age = 24
personDtl(3) = personDtlCrnt 'Write back.

. , , , .

.