Just check the file name with "/" at the end of it.
import zipfile
def isdir(z, name):
return any(x.startswith("%s/" % name.rstrip("/")) for x in z.namelist())
f = zipfile.ZipFile("sample.zip", "r")
print isdir(f, "a")
print isdir(f, "a/b")
print isdir(f, "a/X")
You use this line
any(x.startswith("%s/" % name.rstrip("/")) for x in z.namelist())
because it is possible that the archive does not explicitly contain a directory; just a path with a directory name.
Execution Result:
$ mkdir -p a/b/c/d
$ touch a/X
$ zip -r sample.zip a
adding: a/ (stored 0%)
adding: a/X (stored 0%)
adding: a/b/ (stored 0%)
adding: a/b/c/ (stored 0%)
adding: a/b/c/d/ (stored 0%)
$ python z.py
True
True
False
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