What does + (?! \ D) mean in a regular expression?

Question

I also saw it as + $.

I use

$(this).text( $(this).text().replace(/(\d)(?=(\d{3})+(?!\d))/g, "$1,") );

To convert 10,000 to 10,000, etc.

I think I understand everything:

+5

seanjacob Jul 25 '12 at 11:57

2 answers

?! , -, - ,

+1

mabbas 25 . '12 12:01

Ashe · Accepted Answer · 2012-07-25T12:01:53+0000

I think you are not reading it slightly:

(? = \ d {3}) - if you follow 3 numbers

Note that regexp is actually:

(?=(\d{3})+

i.e. you missed the open wig. All of the following:

(\d{3})+(?!\d)

(?= ... ), - , , , .

(?!\d) , a \d (.. ) , :

"$1,", .. .

, , , !