The program does not work properly

Question

I tried running this simple code:

puts 4
i = gets
puts i

It "works", but the console asks for a string, and then prints 4andi

0

Gilad naaman Jul 05 '11 at 7:34

5 answers

Instead of an explicit call $stdout.flush:

$stdout.sync = true

+1

Victor moroz Jul 05 '11 at 13:56

, ruby 1.8.7, 1.9.2 ree. ?

0

Matt Connolly 05 . '11 7:37

? . bash:)

0

Riccardo 05 . '11 7:38

, . , "" , , . , .

, , ?

, , : , STDIN STDERR. .

if you want to make sure that the text is displayed before something happens (as in this example), use the "flush" command, as Yossi suggests.

0

Arsen7 Jul 05 '11 at 8:49

Yossi · Accepted Answer · 2011-07-05T07:39:09+0000

Add a call flushto gets:

$stdout.flush