I am new to Java and have encountered this problem. I tried the search but did not get the correct answer.
I have a string like
String name = anything 10%-20% 04-03-07
Now I need to create a url string with this string name, as shown below.
http://something.com/test/anything 10%-20% 04-03-07
I tried replacing spaces with% 20 and now I get a new url as
http://something.com/test/anything%2010%-20%%2004-03-07
When I use this url and run it in firefox, it just works fine, but when processing in Java it seems to throw
Exception in thread "main" java.lang.IllegalArgumentException
at java.net.URI.create(Unknown Source)
at org.apache.http.client.methods.HttpGet.<init>(HttpGet.java:69)
Caused by: java.net.URISyntaxException: Malformed escape pair at index 39 :
at java.net.URI$Parser.fail(Unknown Source)
at java.net.URI$Parser.scanEscape(Unknown Source)
at java.net.URI$Parser.scan(Unknown Source)
at java.net.URI$Parser.checkChars(Unknown Source)
at java.net.URI$Parser.parseHierarchical(Unknown Source)
at java.net.URI$Parser.parse(Unknown Source)
at java.net.URI.<init>(Unknown Source)
... 6 more
This is a code throw error
HttpClient httpclient = new DefaultHttpClient();
HttpGet httpget = new HttpGet(url);
HttpResponse response = httpclient.execute(httpget);
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