Since all objects are created using the "new" in Java, does this mean that they are all created on the heap?

The purpose of this query is to compare one aspect of Java and C ++ related to the β€œnew” operator.

Now I know that in C ++ there are two ways to create objects; with or without a "new" operator. In the absence of this operator, space is not allocated in the heap area, while in its presence, space is allocated in the heap area.

What about java? I notice that the β€œnew” operator is used to create each object. Even arrays are created using the "new" operator. Does this mean that in Java there is only one place for objects to exist - that is, a heap area?

Thank.

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class Test {
    void show() {
        System.out.println("Test::show() called");
    }
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public class Main {
    public static void main(String[] args) {
        Test t; 
        t.show(); // Error here because t is not initialed
    }

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class Test {
    void show() {
        System.out.println("Test::show() called");
    }
}      
public class Main {
    public static void main(String[] args) {
        Test t = new Test(); //all objects are dynamically allocated
        t.show(); // No error 
    }
}
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