Compact syntax for getting list header as an option

Question

Is there a compact way to get the list title as Some when the list is not empty, and None otherwise?

This is what I'm doing right now

val ms = moves.filter { ...some predicate... }
if (ms.nonEmpty) Some(ms.head) else None

+5

Janek bogucki Jan 22 '13 at 21:05

2 answers

, , , ( Scalaz)

implicit class boolean2Option(val value: Boolean) extends AnyVal {
  def option[A](f: => A) = if (value) Some(f) else None
}

:

if (condition) Some(result) else None

:

condition option result

+1

Tim 22 . '13 23:33

Rex kerr · Accepted Answer · 2013-01-22T21:09:39+0000

Give it a try headOption. API documents are your friend.

Note that it findperforms exactly filterplus headOption: it takes one element, if any, and puts it in an option, and otherwise gives None.