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Difference between two dates in exact hours in SQL

I would like to calculate the exact time difference between two datetime variables. The difference in hours should be like this:

1.5
2
6.25

Someone please help ... Thanks in advance ...

+5
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5 answers

You can use DATEDIFFto find out the difference in minutes and convert it to hours:

select datediff(mi, startdate, enddate)

Assuming 1.5 means 1 hour and 30 minutes, you can simply divide the result by 60:

select datediff(mi, startdate, enddate) / 60.0
+18
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it will help you ....

  Declare @Date1 dateTime
  Declare @Date2 dateTime 
  Set @Date1 = '22:30:00'   
  Set @Date2 = '00:00:00'
  Select Cast((@Date1 - @Date2) as Float) * 24.0
+3
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, .

declare @date1 datetime
declare @date2 datetime

select @date1 = GETDATE();
select @date2 = '2013-02-02 14:05'

select DATEDIFF(hh, @date2, @date1)


Results
-----------
71

(1 row(s) affected)
+2

:

declare @dt1 datetime, @dt2 datetime, @Seconds int
select @dt1='2013-02-05 14:05:55.113', @dt2 =getdate()
set @Seconds=datediff(second, @dt1, @dt2)

    declare @Hour nvarchar(50)
    declare @Min nvarchar(50)
    declare @MinTemp int        
    if @Seconds >0 
    begin
    set @Hour=cast((@Seconds / 3600) as nvarchar(20)) +' Hrs '
    set @MinTemp= (@Seconds % 3600) / 60
    set @Min=cast(@MinTemp as nvarchar(20))
    if  @MinTemp<10 
        select @Hour+'0'+@Min +' Min'
    else
        select @Hour+@Min +' Min'
    end
    else 
    select '00 Hrs 00 Min'
+1

: MS-SQL

 Declare @InTime datetime='2017-11-27 10:00:00',
 @OutTime datetime='2017-11-27 11:15:00'

 SELECT CONVERT(varchar(5),DATEADD(minute,DATEDIFF(minute,@InTime,@OutTime),0), 114)
 -----------
 Result
 01:15
0

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