Now that I understand your question a little better, this is pretty straight forward:
def takeLastSuccess[A, B](seq:Seq[ValidationNEL[A, B]]) =
seq.sequence[({type l[a] = ValidationNEL[A, a]})#l, B].map(_.last)
When you execute a Scala sequence, type problems arise, so you need to use a lambda type. Consistency is a good shortcut to go from Seq [Something [X]] to Something [Seq [X]]. Finally, we simply match success and get the last B from sequence B.
, , REPL:
scala> import scalaz._, Scalaz._
import scalaz._
import Scalaz._
scala> type ExceptionsOr[A] = ValidationNEL[Exception, A]
defined type alias ExceptionsOr
scala> val successResults: Seq[ExceptionsOr[Int]] = Seq(
| "13".parseInt.liftFailNel, "42".parseInt.liftFailNel
| )
successResults: Seq[ExceptionsOr[Int]] = List(Success(13), Success(42))
scala> val failResults: Seq[ExceptionsOr[Int]] = Seq(
| "13".parseInt.liftFailNel, "a".parseInt.liftFailNel, "b".parseInt.liftFailNel
| )
failResults: Seq[ExceptionsOr[Int]] = List(Success(13), Failure(NonEmptyList(java.lang.NumberFormatException: For input string: "a")), Failure(NonEmptyList(java.lang.NumberFormatException: For input string: "b")))
scala> def takeLastSuccess[A, B](seq:Seq[ValidationNEL[A, B]]) = seq.sequence[({type l[a] = ValidationNEL[A, a]})
takeLastSuccess: [A, B](seq: Seq[scalaz.Scalaz.ValidationNEL[A,B]])scalaz.Validation[scalaz.NonEmptyList[A],B]
scala> takeLastSuccess(successResults)
res0: scalaz.Validation[scalaz.NonEmptyList[Exception],Int] = Success(42)
scala> takeLastSuccess(failResults)
res1: scalaz.Validation[scalaz.NonEmptyList[Exception],Int] = Failure(NonEmptyList(java.lang.NumberFormatException: For input string: "a", java.lang.NumberFormatException: For input string: "b"))