I am unofficially following the python CS61A course through Berkely, and I'm absolutely stumped by one simple assignment, which requires me to provide only one expression at the very end of the provided template. Here is the problem code:
def square(x):
return x*x
def compose1(f, g):
"""Return a function of x that computes f(g(x))."""
return lambda x: f(g(x))
from functools import reduce
def repeated(f, n):
"""Return the function that computes the nth application of f, for n>=1.
f -- a function that takes one argument
n -- a positive integer
>>> repeated(square, 2)(5)
625
>>> repeated(square, 4)(5)
152587890625
"""
assert type(n) == int and n > 0, "Bad n"
return reduce(compose1, "*** YOUR CODE HERE ***" )
repeated(square, 2)(5)
I tried everything to make this work. It seems to me that this return should do this:
return reduce(compose1, range(n))
But I'm not even close. Compose1 takes two arguments (f, g), and they must be functions. But when the return statement calls "compose1", "compose1" uses "0" for "f" and "n" for "g". But 'f' and 'g' must be a function called - squared
What am I missing.
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