I work with a ridiculously large code base and I need to move the file from one package to another. However, I don't have the entire code base locally, so I'm not sure if I found and updated every link to the source file. To ensure that I don't break anything, I would like to leave the original file and just extend the new file that I created. Ideally, they would have the same name. Overtime, I plan to refuse and delete the old file, but at the moment this seems like the most reliable solution. However, I cannot figure out how to make it work in Java.
Here is a new class:
package myproject.util.http;
import javax.servlet.http.HttpServlet;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public abstract class MyServlet extends HttpServlet
{
public void service (HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException
{
}
}
Here is an old class that extends the new:
package myproject.util.net;
import myproject.util.http.MyServlet;
public abstract class MyServlet extends myproject.util.http.MyServlet
{
}
Sorry, I get an error message:
MyServlet is already defined in this compilation unit
Is this possible, or will I have to come up with a new name for the parent class.