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How to display data in datagridview from access database

I have codes here displaying data in a datagridview from an access database. I have different rows, but only the last row of data in the database is displayed. I do not know what is wrong in my code.

    dataGridView1.Columns.Add("UserID", "UserID");
    dataGridView1.Columns.Add("FirstName", "FirstName");
    dataGridView1.Columns.Add("MI", "MI");
    dataGridView1.Columns.Add("LastName", "LastName");
    dataGridView1.Columns.Add("Birthdate", "Birthdate");
    dataGridView1.Columns.Add("Address", "Address");
    dataGridView1.Columns.Add("UserName", "UserName");
    dataGridView1.Columns.Add("UserPassword", "UserPassword");
    dataGridView1.Columns.Add("Rights", "Rights");


    OleDbConnection conn = new OleDbConnection(@"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=\\SISC-STRONGHOLD\MIS!\wilbert.beltran\SEEDBucksDbase.accdb");
    conn.Open();
    OleDbCommand cmd = new OleDbCommand();
    cmd.Connection = conn;
    cmd.CommandText = "SELECT * From TableAcct";
    OleDbDataReader reader = cmd.ExecuteReader();
    while (reader.Read())
    {
        dataGridView1.Rows.Add();

        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["UserID"].Value = reader[0].ToString();
        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["FirstName"].Value = reader[1].ToString();
        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["MI"].Value = reader[2].ToString();
        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["LastName"].Value = reader[3].ToString();
        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["Birthdate"].Value = reader[4].ToString();
        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["Address"].Value = reader[5].ToString();
        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["UserName"].Value = reader[7].ToString();
        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["UserPassword"].Value = reader[8].ToString();
        dataGridView1.Rows[dataGridView1.Rows.Count - 1].Cells["Rights"].Value = reader[9].ToString();
    }
    conn.Close();
}
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4 answers

You can directly bind dataGridView1with OleDbDataAdapter. Make sure that the column names in the datagridview match the field names returned by the query, so it will contain empty columns and create a different column for each field.

string connStr = @"Provider=Microsoft.ACE.OLEDB.12.0;
        Data Source=\\SISC-STRONGHOLD\MIS!\wilbert.beltran\SEEDBucksDbase.accdb";
string query = "SELECT * From TableAcct";
using(OleDbConnection conn = new OleDbConnection(connStr))
{
    using(OleDbDataAdapter adapter = new OleDbDataAdapter(query, conn))
    {
        DataSet ds = new DataSet();
        adapter.Fill(ds);
        DataGridView1.DataSource= ds.Tables[0];
    }
}
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Please use this code to display your data in a datagridview in C # .net

 OleDBConnection con=new      OleDBConnection("Copy your database database path and paste it");
    con.open();
    Dataset ds=new Dataset();
         OleDBDataAdapter sdr=new      OleDBDataAdapter("select * from table_name",con);
    sdr.Fill(ds);
    datagridview1.Datasource=ds.tables[0];
    con.close();
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public partial class WebForm1 : System.Web.UI.Page
{
    public String name,type,rvw;


    public void Page_Load(object sender, EventArgs e)
    {
        SqlConnection con = new SqlConnection(@"Data Source=(LocalDB)\v11.0;AttachDbFilename=C:\Users\Uz!\Documents\Data_Ware.mdf;Integrated Security=True;Connect Timeout=30");
        SqlDataAdapter sda = new SqlDataAdapter("Select * From CoffeeDB  ", con);
        DataTable dt = new DataTable();
        sda.Fill(dt);

        GridView.DataSource = dt;
    }
}
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string con= "SERVER=localhost; user id=root; password=; database=dbname";

MySqlConnection connect = new MySqlConnection(con);
connect.Open();
try
{
string sqlQuery = "SELECT * FROM DATA WHERE date(date) = date(now())";
MySqlDataAdapter da = new MySqlDataAdapter(sqlQuery, connect);
DataTable ds = new DataTable();
da.Fill(ds);
Datagrid.DataSource = ds;
}
catch(Exception ex)
{
Console.WriteLine(ex.ToString());
}
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