Pointer initialization

Question

Currently, I am confused with the following statement: although this statement would give an error at compile time, but it is not.

// statement 1:
someclass* q(someclass());

I understand if this statement was that way

// statement 2:
someclass* q(&someclass());

I would like to know why statment 1 does not generate an error, or even if it is valid (is there anything that I am missing behind the curtains?)

+5

Rajeshwar Mar 15 '13 at 10:57

2 answers

1 . q , someclass, someclass.

+3

Mankarse 15 . '13 22:59

Andy Prowl · Accepted Answer · 2013-03-15T22:59:40+0000

I would like to know why statment 1 does not generate an error or even if it really is

, , , , : q, someclass , , , someclass. Vexing Parse.

: q someclass , someclass(). , , someclass() , .