I have such a data model
public class NewsItem
{
public virtual int Id { get; set; }
public virtual string NewsTitle { get; set; }
public virtual string NewsContent { get; set; }
public virtual byte[] NewsImage { get; set; }
public virtual DateTime DateAdded { get; set; }
public virtual bool IsLive { get; set; }
}
Then I output this data through the view like this:
@model BusinessObject.Domain.NewsItem
<div class="row-fluid">
<h3>
@Html.ValueFor(model => model.NewsTitle)
</h3>
<div class="span5">
<img src="~/Content/images/stock.jpg" />
</div>
<div class="span7">
<p>
@Html.ValueFor(model => model.DateAdded)
</p>
<p>
@Html.ValueFor(model => model.NewsContent)
</p>
</div>
</div>
Then I save the data using _db.SaveChanges () in my controller as follows:
[Authorize]
[HttpPost]
public ActionResult Create(CreateNewsViewModel input)
{
if (ModelState.IsValid)
{
var news = new NewsItem();
news.NewsTitle = input.nTitle;
news.NewsContent = input.nContent;
news.DateAdded = input.nDateAdded;
news.IsLive = input.nIsLive;
Mydb data = new Mydb();
data.NewsItems.Add(news);
data.SaveChanges();
return View("Index", data.NewsItems);
}
else
{
return View(input);
}
}
I currently do not have an image download bit. How can i do this? In my db, I have a binary field, and my data type in my object is byte []. But I donβt know where I need to handle image upload?
Do I need a separate action that returns a view? Some pointers to this would be great.
Greetings
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