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Python furl library - Is there a way to add a parameter to a url without url encoding?

I have a url that I need to add an api key as a parameter. The key has% and other characters in it and should not be encoded in url, is there any way to do this with furl ?

Here is my current code:

request_url = furl('http://www.domain.com/service/') \
    .add({
    'format'     : 'json',
    'location'      : address_line_1 + ',' + city + ',' + state,
    'key'           : APP_KEY
}).url
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1 answer

I have a url that I need to add an api key as a parameter. The key has% and other characters in it and should not be encoded in the URL

It can not be true. It must be encoded in the URL. Otherwise, you will receive either an invalid URL or a URL that does not mean what you want.

, , 123%456%789. http://www.domain.com/service/?format=json&key=123%25456%25789, - 123%456%789, . http://www.domain.com/service/?format=json&key=123%456%789, - 123E6x9, .

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request_url = furl('http://www.domain.com/service/?key={}'.format(APP_KEY)) \
    .add({
    'format'     : 'json',
    'location'      : address_line_1 + ',' + city + ',' + state,
}).url

Hacky? , , , furl, , , .

+1

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