Here is an example of a hotel:
CREATE TABLE `hotels` (
`HotelNo` varchar(4) character set latin1 NOT NULL default '0000',
`Hotel` varchar(80) character set latin1 NOT NULL default '',
`City` varchar(100) character set latin1 default NULL,
`CityFR` varchar(100) character set latin1 default NULL,
`Region` varchar(50) character set latin1 default NULL,
`RegionFR` varchar(100) character set latin1 default NULL,
`Country` varchar(50) character set latin1 default NULL,
`CountryFR` varchar(50) character set latin1 default NULL,
`HotelText` text character set latin1,
`HotelTextFR` text character set latin1,
`tagsforsearch` text character set latin1,
`tagsforsearchFR` text character set latin1,
PRIMARY KEY (`HotelNo`),
FULLTEXT KEY `fulltextHotelSearch` (`HotelNo`,`Hotel`,`City`,`CityFR`,`Region`,`RegionFR`,`Country`,`CountryFR`,`HotelText`,`HotelTextFR`,`tagsforsearch`,`tagsforsearchFR`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_german1_ci;
In this table, for example, we have only one hotel with the name Region = "Graubünden" (note the umlaut symbol)
And now I want to achieve the same search match for the phrases: “robberies” and “Graubunden”
It is simple using MySql built into sorting in a regular search as follows:
SELECT *
FROM `hotels`
WHERE `Region` LIKE CONVERT(_utf8 '%graubunden%' USING latin1)
COLLATE latin1_german1_ci
This is great for robbery and graubunden and as a result I get the correct result, but the problem is when we do a full MySQL text search
What is wrong with this SQL statement ?:
SELECT
*
FROM
hotels
WHERE
MATCH (`HotelNo`,`Hotel`,`Address`,`City`,`CityFR`,`Region`,`RegionFR`,`Country`,`CountryFR`, `HotelText`, `HotelTextFR`, `tagsforsearch`, `tagsforsearchFR`)
AGAINST( CONVERT('+graubunden' USING latin1) COLLATE latin1_german1_ci IN BOOLEAN MODE)
ORDER BY Country ASC, Region ASC, City ASC
This does not return any result. Any ideas where the dog is buried?