How to remove all punctuation marks in a string? (Python)

Question

For instance:

asking="hello! what your name?"

Can I do it?

asking.strip("!'?")

+5

Wuchun aaron Apr 17 '13 at 3:29

4 answers

import string

asking = "".join(l for l in asking if l not in string.punctuation)

+12

thkang Apr 17 '13 at 3:31

, .

asking="hello! what your name?"
asking = ''.join([c for c in asking if c not in ('!', '?')])
print asking

0

marcin_koss 17 . '13 3:35

The strip will not work. It removes only leading and trailing instances, and not everything in between: http://docs.python.org/2/library/stdtypes.html#str.strip

Fun with a filter:

import string
asking = "hello! what your name?"
predicate = lambda x:x not in string.punctuation
filter(predicate, asking)

0

Brenden brown Apr 17 '13 at 3:43

Øyvind Robertsen · Accepted Answer · 2013-04-17T03:36:29+0000

Actually a simple implementation:

out = "".join(c for c in asking if c not in ('!','.',':'))

and keep adding any other punctuation marks.

A more efficient way would be

import string
stringIn = "string.with.punctuation!"
out = stringIn.translate(stringIn.maketrans("",""), string.punctuation)

Edit: Here are some more discussions of efficiency and other implementations: Best way to block punctuation from a string in Python