Not sure if this is the answer to your question, but this is a simple recursive implementation to find the result below.
package main
import "fmt"
func main() {
values := [][]int{}
row1 := []int{1, 2, 3}
row2 := []int{4, 5, 6}
row3 := []int{7, 8, 9}
values = append(values, row1)
values = append(values, row2)
values = append(values, row3)
fmt.Println(getPermutation(values))
}
func getPermutation(vids [][]int) [][]int {
toRet := [][]int{}
if len(vids) == 0 {
return toRet
}
if len(vids) == 1 {
for _, vid := range vids[0] {
toRet = append(toRet, []int{vid})
}
return toRet
}
t := getPermutation(vids[1:])
for _, vid := range vids[0] {
for _, perm := range t {
toRetAdd := append([]int{vid}, perm...)
toRet = append(toRet, toRetAdd)
}
}
return toRet
}
https://play.golang.org/p/f8wktrxkU0
The output above the snippet:
[[1 4 7] [1 4 8] [1 4 9] [1 5 7] [1 5 8] [1 5 9] [1 6 7] [1 6 8] [1 6 9] [2 4 7] [2 4 8] [2 4 9] [2 5 7] [2 5 8] [2 5 9] [2 6 7] [2 6 8] [2 6 9] [3 4 7] [3 4 8] [3 4 9] [3 5 7] [3 5 8] [3 5 9] [3 6 7] [3 6 8] [3 6 9]]
source
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