I'm trying to figure out where my mistake is, because it is not possible for JS to fail in math!
In the HTML form, I have a choice and 9 text input. Then on JS I compare the entered text.
My problem is this: If I write to
new_da3 = 1400
new_a3 = 1900
JS will say ok3.
If I write in
new_da3 = 1900
new_a3 = 1400
JS will say no3!
BUT if I write to
new_da3 = 1500
new_a3 = 800
JS WILLL SAY ok3!
Why? Is not 1500 more than 800?
Thank!
HTML:
<form>
<select id="new_nrp" onchange="selNrP(this.value);" style="background-color:#F00; color:#FFF">
<option value="" selected="selected"></option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>
<?php
for($i=1; $i<=3; $i++){
print '<input type="text" size="5" maxlength="5" id="new_da'.$i.'">
<input type="text" size="5" maxlength="5" id="new_a'.$i.'">';
}
?>
<input type="submit" class="buttongreen" onClick="test()" value="Try the test function!">
</form>
Js
function test(){
var new_da1 = document.getElementById('new_da1').value
var new_a1 = document.getElementById('new_a1').value
var new_da2 = document.getElementById('new_da2').value
var new_a2 = document.getElementById('new_a2').value
var new_da3 = document.getElementById('new_da3').value
var new_a3 = document.getElementById('new_a3').value
var new_nrp = document.getElementById('new_nrp').value
switch(new_nrp){
case '3':
if(new_a2 < new_da3 && new_da3 <= new_a3){
alert('ok3')
} else {
alert('no3')
return
}
case '2':
if(new_a1 < new_da2 && new_da2 <= new_a2){
alert('ok2')
} else {
alert('no2')
return
}
case '1':
if(new_da1 <= new_a1){
alert('ok1')
} else {
alert('no1')
return
}
break;
default:
alert("Why are you here?");
return;
}
}
source
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