How do I create multiple generators for list recognition in F #?

Question

I'm trying to write something like this

[(x,y)|x<- [1,2,3], y <- [’a’,’b’]]
 => [(1,’a’),(1,’b’),(2,’a’),(2,’b’),(3,’a’),(3,’b’)]

+3

unj2 Mar 17 '11 at 3:27

3 answers

just another interesting way

[1;2;3] |> List.map ( fun X -> ['a';'b'] |> List.map (fun A -> X,A) )

+2

Masha Mar 17 '11 at 5:46

equivalent to F #.

List.zip [1;2;3] ['a';'b';'c']

-2

nyi nyi thann Mar 17 '11 at 3:33

kvb · Accepted Answer · 2011-03-17T03:36:06+0000

[for x in [1;2;3] do
 for y in ['a';'b'] do
 yield x,y]