How to explain the following code?

Question

I have two questions about C ++ programming.

1) int a[10] = new int*;is this statement valid?

2) extern void test(int a,int b) throw(const char *, RangeErr);

what does test () do, throw (const char *, RangeErr) means throw two exceptions? and what is RangeErr? and why extern? what does this function do?

+3

cong May 05, '11 at 20:27

4 answers

Drew Hall · Answer 1 · 2011-05-05T20:38:52+0000

1) Not valid. An array is not a pointer (although it can be implicitly converted to one in some contexts). Try instead:

int* a = new int[10];

2) ( ). , " ", , . , "".

throw , ( C- RangeErr, , , , ). - , std:: (), . , , , , , ++ 11 .

David Thornley · Answer 2 · 2011-05-05T20:41:36+0000

throw . , throw () , , . . " " Herb Sutter, - ++.

Jonathan Grynspan · Answer 3 · 2011-05-05T20:35:03+0000

1) . .

2) test() - . throw(...) , . RangeErr - . extern , (.. ).

Matthew Clark · Answer 4 · 2011-05-05T20:36:34+0000

1), No

2), , "const char *" "RangeErr". , RangeErr , , , , . , (dll, - ), api , , . ^^ , .