Copy c char pointer to non char pointer

Question

Is there a problem with this?

char* field = new char[2];
field[0] = 'S';
field[1] = '\0';

char c = *field;

will always be equal to 's'?

+3

okami May 11, '11 at 22:45

4 answers

fbafelipe · Answer 1 · 2011-05-11T22:47:43+0000

No problem with that, c will always be "S".

Will a · Answer 2 · 2011-05-11T22:47:24+0000

This is perfectly normal - and c will always be equal to "S". Highlighting fielda type pointer charwill result in char.

Anomie · Answer 3 · 2011-05-11T22:53:16+0000

The problem is that new char[2]C is not syntax. However, the general idea is correct: cthere will always be an "S".

Gustavo mori · Answer 4 · 2011-05-12T00:35:30+0000

There is nothing wrong. When you look for a field array in a string

char c = *field;

what you are actually requesting is the value of the first element of the array, in this case "S".