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PHP: getting image from MySQL using PDO

I am refactoring old code, including rewriting basic mysql queries to use PDO.

The following works brilliantly in all browsers and for all types of images:

$query = 'SELECT image FROM image WHERE imageid=' . $image_id;
$result = mysql_query($query, $db_conn); querycheck($result);
header("Content-type: image");
echo mysql_result($result, 0);

Unfortunately, however, I rewrite it using PDO, it does not work. I went through all the PDO documentation and standard web search, but none of the recommendations / solutions work.

How to easily get and display from MySQL using PDO and display it?

Edit 1:

Matthew Ratsloff gives what should be the obvious answer below, but that doesn't work. Here is the actual code that I am testing with PDO (and I have tried many options / options):

$connectstring_temp = 'mysql:host=' . $A . ';dbname=' .$B;
$dbh_temp = new PDO($connectstring_temp, $login, $password);
#$dbh_temp->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
#$dbh_temp->setAttribute(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY,true);

$sql = "SELECT image FROM image WHERE imageid=" . $image_id;
$query = $dbh_temp->prepare($sql);
$query->execute();

$query->bindColumn(1, $image, PDO::PARAM_LOB);
$query->fetch(PDO::FETCH_BOUND);
header("Content-Type: image");
echo $image;

, $image_id . . PDO .

+3
4

imageid PDO::PARAM_LOB:

$sql = "SELECT image FROM image WHERE imageid=:id";
$query = $db_conn->prepare($sql);
$query->execute(array(':id' => $image_id));

$query->bindColumn(1, $image, PDO::PARAM_LOB);
$query->fetch(PDO::FETCH_BOUND);
header("Content-Type: image");
echo $image;

, , (, image/png).

+3

PDO:

public function getImage($id){
    $sql = "SELECT * FROM images WHERE id = ?";
    $sth = $this->dbh->prepare($sql);

    $sth->bindParam(1,$id);
    $sth->execute();


    $num = $sth->rowCount();
    if( $num ){
        $row = $sth->fetch(PDO::FETCH_ASSOC);
        header("Content-type: ".$row['type']);
        print $row['image'];
        exit;
    }else{
        return null;
    }
}

type - data type(column name), image/png image/gif
image - image data(column name) LOB
$this->dbh
, , JS, JavaScript - ajax

0

Image Blobs php GET... 100% ... , blob :

image.php:

<?php
$db = new PDO('mysql:host=localhost;dbname=anything; charset=utf8', 'account','password');
if (isset($_GET['imageid'])) {
    $result = $db->prepare("SELECT image FROM image where imageid = ?");
    if ($result->execute(array($_GET['imageid']))) {
        $row=$result->fetch();
        echo $row['pic']; //this prints the image data, transforming the image.php to an image
        }
    } // you can put an "else" here to do something on error...
?>

script... :

<?php
$db = new PDO('mysql:host=localhost;dbname=anything; charset=utf8', 'account','password');
//... some code to do your job, where you get your imageid from
$imageid=...
?>
<img src="./image.php?imageid=<?php echo $imageid;?>">
0

dabase, , .

 GetMessage (); }? >
<?php 
#the folder where the images are saved 
$target = "image_uploads/";
$image_name = (isset($_POST['image_name']));

$query = ("SELECT user_id ,image_name FROM tish_images");
$image_show= $con-> prepare($query);
$image_show->execute();
while($record =$image_show->fetch(PDO::FETCH_ASSOC)) {
#this is the Tannery  operator to replace a pic when an id do not have one
$photo = ($record['image_name']== null)? "me.png":$record['image_name'];
#display image 
echo '<img src="'.$target.$photo.'">';
echo $record['user_id'];
}
?>
-2
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