Regular expression. how to exclude a substring from the result after it matches the pattern

Question

I wonder how I can exclude a substring from the result after it matches the pattern. Example:

<a href="?page1"><?php __('string1');?></a>
<a href="?page2"><?php __("string2");?></a>

I want to get only the strings passed as parameters to the __ () function. I tried this regex:

'/__\(((\'([^\']+)\')|(\"([^\"]+)\"))/'

but returns "string1" and "string2" enclosed in single quotes and double quotes.
how can i exclude single quotes and double quotes?

+3

ahmedhelmy007 May 16 '11 at 5:24

4 answers

:

'/__\((?:'([^']+)|"([^"]+))/'

+2

sawa 16 '11 5:27

Do you want to try using non-exciting bands - (?:ABC)

0

manojlds May 16 '11 at 5:33

You can use Lookahead and Lookbehind or make the string inside quotation marks a group.

0

daalbert May 16 '11 at 5:41

stema · Accepted Answer · 2011-05-16T06:16:49+0000

try it

'/__\(('|")([^\1]+)\1\)/'
       ^1^  ^^2^^^

, , . , , (?:), , . . . ' " 1. backreference \1 , .

2. , .