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The image appears when the button is pressed.

How to create a hidden image when you click the submit button?

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5 answers

You are lucky that I had a ready-made HTML page:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
  <head>
    <meta content="text/html; charset=UTF-8" http-equiv="content-type" /> 
    <meta charset="utf-8" />

    <title>Test</title>

    <style type="text/css">
      .hidden {
        display: none;
      }
    </style>
  </head>

  <body>
    <form>
      <input type="submit" id="submit" onclick="document.getElementById('hidden').style.display = 'block';" />
     </form>

     <img id="hidden" class="hidden" src="foo.png" />
  </body>
</html>
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Using jQuery:

<img id="image1" src="myimage.jpg" style="display:none;" width="120" height="120"/>

<input type="submit" name="submit" value="submit" onclick"$('#image1').show()"/>
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, . - , , .

<img src="thesource" class="hidden">

document.getElementById("theid").className = ""; // remove the hidden class.


.classHidden {
     display: none;
}
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document.getElementById("submitBtn").onclick = function() {
 document.getElementById("imageTag").style.display="block";
 return true;
}
0

<img class="image_file src="image.jpg" />
<input type="submit" id="submit_button" name="submit_button" />

css:

.image_file
{
display:none;
}

jquery:

$('#submit_button').click(function(
    $('.image_file').show();
));

javascript, , .

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