I am trying to convert some Verilog code that produces a slower clock with a faster clock for the UART module. Verilog source code is based on a module on fpga4fun.com, and this is my attempt to translate it for my VHDL based project.
entity baud_generator is
generic(
f_clk : integer := 50000000; -- default: 50 MHz
baud : integer := 115200; -- default: 115,200 baud
accum_width : integer := 16;
accum_inc : integer := (baud sll accum_width) / f_clk
);
port(
clock : in std_logic;
reset_n : in std_logic;
enable : in std_logic;
baud_clock : out std_logic
);
end entity baud_generator;
However, my Aldec-HDL compiler does not like the following line:
accum_inc : natural := (baud sll accum_width) / f_clk
Here is the exact error message:
# Error: COMP96_0300: baud_generator.vhd : (20, 52): Cannot reference "f_clk" until the interface list is complete.
# Error: COMP96_0300: baud_generator.vhd : (20, 28): Cannot reference "baud" until the interface list is complete.
# Error: COMP96_0071: baud_generator.vhd : (20, 28): Operator "sll" is not defined for such operands.
# Error: COMP96_0104: baud_generator.vhd : (20, 27): Undefined type of expression.
# Error: COMP96_0077: baud_generator.vhd : (20, 27): Assignment target incompatible with right side. Expected type 'INTEGER'.
In verilog, I have something like this:
module baud_generator(
input clock,
input reset_n,
input enable,
output baud_clock
);
parameter f_clock = 50000000;
parameter baud = 115200;
parameter accum_width = 16;
parameter accum_inc = (baud << accum_width) / f_clock;
//...
endmodule
What do I need to change on this line to make the compiler happy? Can generic drugs be used together?
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