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Run OR on two sha1sum hash outputs

I want to execute sha1sum file1and sha1sum file2and execute bitwise OR with them using bash. The output must be printable, i.e. 53a23bc2e24d039 ... (160 bits)

How can i do this?

I know

echo $ ((0xa | 0xb)), but how to increase to 40 hexadecimal digits?

thank

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4 answers

I don't think you really want 160-bit inclusive OR, but if you do:

split32 () {
  x='s/\(........\)\(........\)\(........\)\(........\)\(........\)/'
  x=$x'0x\1 0x\2 0x\3 0x\4 0x\5/'
  sed -e "$x"
}

(sha1sum $1 | split32; sha1sum $2 | split32) | (
    read a1 b1 c1 d1 e1 x1
    read a2 b2 c2 d2 e2 x2
    a=$(($a1 | $a2))
    b=$(($b1 | $b2))
    c=$(($c1 | $c2))
    d=$(($d1 | $d2))
    e=$(($e1 | $e2))
    printf '  %08x%08x%08x%08x%08x\n' $a1 $b1 $c1 $d1 $e1
    printf '+ %08x%08x%08x%08x%08x\n' $a2 $b2 $c2 $d2 $e2
    printf '= %08x%08x%08x%08x%08x\n' $a  $b  $c  $d  $e 
)
$ bash bigOr.sh fun.tar fun.tgz
  e515d3813b17c36b9a7d29f7aea3e79e264449b7
+ 4f201513105c301944d0a0ba5864d9f07544ca76
= ef35d7933b5ff37bdefda9fffee7fffe7744cbf7
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Try the following:

val1=$(sha1sum file1)
val1=${val1% *}
val2=$(sha1sum file2)
val2=${val2% *}
val3=$(( 0x$val1 | 0x$val2 ))
printf "%x\n" $val3
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bash 64 . , .

- , OR . "printable output" printf "%x" $val .

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you can use gawk

sha1sum file1 file2 | awk '{sh1=$1;getline;sh2=$1;print or(sh1,sh2);exit}'
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