Currently, when I run this code, it shows me a graph, as shown above, I want to draw the graph that I showed. Currently, when drawing a graph symmetrical about (0,0), I think that forcing him to draw from (0, -3) or (0, <-2), this work should be done. Is there any other way to do this?
Current Code:
public class Profile {
double last=0;
ChartFrame frame1;
JToolBar jt=new JToolBar();
public void generateProfile(int[] pointValue,double[] distance){
ArrayList pv=new ArrayList();
ArrayList dist=new ArrayList();
pv.add(pointValue);
dist.add(distance);
int min=pointValue[0];
for(int i=0;i<pv.size();i++){
if(pointValue[i]<min){
min=pointValue[i];
}
}
for(int i=0;i<dist.size();i++){
System.out.print(distance[i]);
}
XYSeries series = new XYSeries("Average Weight");
for(int i=0;i<pointValue.length;i++){
series.add(last,pointValue[i]);
last=distance[i];
}
XYDataset xyDataset = new XYSeriesCollection(series);
JFreeChart chart= ChartFactory.createXYAreaChart("Profile View Of Contour", "Distance", "Contour Value", xyDataset, PlotOrientation.VERTICAL, true, true, false);
ValueAxis rangeAxis = chart.getXYPlot().getRangeAxis();
rangeAxis.setLowerBound(-3);
frame1=new ChartFrame("XYLine Chart",chart);
JButton saveimg=new JButton(new AbstractAction("Save as Image"){
public void actionPerformed(ActionEvent e) {
}
});
jt.add(saveimg);
frame1.add(jt, BorderLayout.NORTH);
frame1.setVisible(true);
frame1.setSize(300,300);
}
public static void main(String ar[]){
Profile pro=new Profile();
int[] pv={2,3,0,5,-2,10};
double[] dist={1,4,8,12,14,20};
pro.generateProfile(pv, dist);
}
}
Parth source
share