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Combination of observables

I have two observables: LoadLocal and LoadServer. LoadLocal loads and returns an item from a local source, and LoadServer retrieves it from the server. I want to combine them into another observable: Load. I want Load to get an element from LoadLocal, and if it is null, I want to return an element from LoadServer. Any ideas how to do this?

thank

Details of the real scenario:

// loadLocal(id) gives me an observable that returns an asset from a local source
Func<Guid, IObservable<IAsset>> loadLocal = Observable.ToAsync<Guid, IAsset>(id => GetLocalAsset(id));

var svcClient = new ServiceClient<IDataService>();
var svc = Observable.FromAsyncPattern<Request, Response>(svcClient.BeginInvoke, svcClient.EndInvoke);

// calling loadServer(id) gives me an observable that returns an asset from a server
var loadServer = id => from response in svc(new Request(id)) select response.Asset;

// so at this point i can call loadServer(id).Subscribe() to get an asset with specified id from the server, or I can call loadLocal(id).Subscribe() to get it from local source.
// however I want another observable that combines the two so I can do: load(id).Subscribe() that gets the asset from loadLocal(id) and if it is null it gets it from loadServer(id)
var load = ???

The following almost gives me the desired result, however both loadLocal (id) and loadServer (id) start up. If loadLocal (id) returns an element, I do not want to run loadServer (id).

var load = id => loadLocal(id).Zip(loadServer(id), (local, server) => local ?? server);
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2 answers

How about this:

loadLocal(id)
    .Where(x => x != null)
    .Concat(Observable.Defer(() => loadServer(id)))
    .Take(1);
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Is something like this possible?

var load = LoadLocal.Zip(LoadServer, (local, server) => local ?? server);
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