How to count the number of lines appearing in a text file with AWK only?

Question

I am writing an AWK script that takes a list of dates and formats it into a list that is easier to read. I could not do that.

The real problem is this. After displaying the list, I want to display how many times “2010” appears in the text file.

How should I do it? I was looking for days, and I came up with absolutely nothing.

+3

user1349126 Apr 22 '12 at 4:52

2 answers

awk -F"2010" 'NF>0 { count += NF-1 } END { print 0+count }

+3

Michael J. Barber Apr 22 '12 at 5:31

Niall byrne · Accepted Answer · 2012-04-22T05:02:44+0000

awk '{ for (i=1;i<=NF;i++) if ( $i == "2010" ) count++ } END { print count }' myfile.txt