Detect python-xmpp timeouts

I have an application that sends xmpp messages. These cases are rare (sometimes none for several days), and then again, possibly, appear in bundles. I don’t want to receive anything, I just want to send. The straightforward approach works with undetected timeouts. The latter is send()not executed (the receiver does not receive anything), but returns without reporting a problem (returns a simple identifier, as if everything was working fine). Only the next call send()then raises an IOError ("Disconnected from server.").

I can do a permanent disconnect / reconnect for each message, but I don’t like it because sometimes it very often disconnects and reconnects (and I don’t know if the servers evaluated it several times per second).

I could try the approach cited as the answer in this question here, but I really don't need to receive XMPP responses.

Question: Is there an easy way to determine the connection timeout before or after sending without trying to send a second message (to spam the recipient if everything works fine)?

My direct approach:

import xmpp

def connectXmppClient(fromJidName, password):
  fromJid = xmpp.protocol.JID(fromJidName)
  xmppClient = xmpp.Client(fromJid.getDomain(), debug=[])
  connection = xmppClient.connect()
  if not connection:
    raise Exception("could not setup connection", fromJid)
  authentication = xmppClient.auth(
    fromJid.getNode(), password, resource=fromJid.getResource())
  if not authentication:
    raise Exception("could not authenticate")
  return xmppClient

def sendXmppMessage(xmppClient, toJidName, text):
  return xmppClient.send(xmpp.protocol.Message(toJidName, text))

if __name__ == '__main__':
  import sys, os, time, getpass
  if len(sys.argv) < 2:
    print "Syntax: xsend fromJID toJID"
    sys.exit(0)
  fromJidName = sys.argv[1]
  toJidName = sys.argv[2]
  password = getpass.getpass()
  xmppClient = connectXmppClient(fromJidName, password)
  while True:
    line = sys.stdin.readline()
    if not line:
      break
    print xmppClient.isConnected()
    id = sendXmppMessage(xmppClient, toJidName, line)
    print id