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Int member function inside a template class

Duplicate question.

I have a class like this:

template <class T>
class foo {
public:        

    foo(){}

    template <int S>
    void bar (){}

}

If this class is called with:

int main(){
    foo<float> m;
    m.bar<1>();
}

It gives an error:

error: expected primary expression before ')' token

deprecated again:

My code is:

#define BOOST_TEST_DYN_LINK
#define BOOST_TEST_MAIN

#include <boost/mpl/list.hpp>
#include <boost/test/unit_test.hpp>
#include <boost/test/test_case_template.hpp>
using namespace boost::unit_test;

#include "foo.hpp"

BOOST_AUTO_TEST_SUITE();

typedef boost::mpl::list<char, int> test_types;

BOOST_AUTO_TEST_CASE_TEMPLATE(test_Mat_constructor_hwd, T, test_types){

    foo<T> m;
    m.bar<1>();
}

BOOST_AUTO_TEST_SUITE_END()

This, however, does not compile, since BOOST_AUTO_TEST_CASE_TEMPLATE does something strange ...

The following text is deprecated:

However, when I call the function with:

foo f;
f.bar<1>();

I get an error message:

A related member function can only be called

If I, however, wrap the bar function in something like void bar1 () {return bar <1> ();}, this will work. I know if T is not known at compile time, it will not compile. But I do not know why the compiler is not smart enough to understand that 1 in f.bar <1> is static?

thank!

+3
2

, , m.bar, , . m.bar<1>() (m.bar<1)>(), . , , bar :

foo<T> m;
m.template bar<1>();
+2

- , ,

class foo {
public:
    foo(){}

    template <int T>
    void bar (){}
 };

int main(){
    foo f;
    f.bar<1>();
}
+1

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