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How to print the string "\ b" in Python

In my compiler class, I decided to write my compiler in Python, since I like programming in Python, although I encounter an interesting problem with the way characters are printed. The lexer I'm writing requires that strings containing form and backspace characters be printed on stdout in a very specific way: enclosed in double quotes and printed as \ f and \ b, respectively. The closest I got:

print("{0!r}".format("\b\f"))

what gives

'\x08\x0c'

Pay attention to single quotes and utf8 coding. The same team with two other characters that I deal with almost works:

print("{0!r}".format("\n\t"))

gives:

'\n\t'

To be clear, a result (including quotation marks) that must conform to the specification,

"\b\f"

, \b \f "\ b" "\ f" , , ... "\" - , Python , , , "\ b\f", .

, , . , . , , , .

EDIT: . , , . , , , "\n" , "\ t". , raw, "\ b" "\ f" , .

, , , , , , , "\n", "\ t", "\ b" , "\ f" escape-, . string.Formatter.

EDIT2: , , - . - :

print('"{0!s}"'.format(a.replace("\b", "\\b").replace("\t", "\\t").replace("\f", "\\f").replace("\n","\\n")))
+3
3
print("{0!r}".format("\b\f".replace("\b", "\\b").replace("\f", "\\f")))

, :

def escape_bs_and_ff(s):
    return s.replace("\b", "\\b").replace("\f", "\\f")

print("{0!r}".format(escape_bs_and_ff("\b\f"))
+3

:

>>> print(r'\b')
    \b
+5
>>> print(r'"\b\f"')
"\b\f"

r , , , , \n, , \n.

0

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