Possible duplicate:
phonegap: open an external link in Safari, not the UIWebView application
I made an HTML5 application for my iPad. this is done natively with telephone service. In my application, I have external links to web pages. However, when I open these links, the external web page opens in my application, and since my iPad does not have a back button, there is no way to return to my application. Even when I close the application and then open it again, the external opens webpage.
I tried to solve the problem with childbrowser, but I have the same problem. Here is the code I used:
openChildBrowser('http://en.wikipedia.org/wiki/Lapis_lazuli',{ showLocationBar: true });">text here</a>
and
<a onclick= "window.plugins.childBrowser.showWebPage('http://en.wikipedia.org/wiki/Lapis_lazuli',{showLocationBar: true});">text here</a>
and of course I tried the usual href. Does anyone have a solution to my problem? Thank you for your time:)
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