Math.Mod in Go returns the integer part instead of the remainder of the floating point

Question

Math.Mod in Go returns the integer part instead of the remainder of the floating point

Golang math.Mod (10, 4) returns 2 - i.e. the integer part of the separation result 2.5 - but should not be a "remainder with a floating point", that is, 0.5?

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floating point go division modulo

metaleap May 18, '12 at 9:32

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1 answer

Evan shaw · Accepted Answer · 2012-05-18T09:36:28+0000

The result is correct. math.Mod returns the remainder, which in this case is really 2. This is equivalent to the% operator, but for floating point numbers.

Math.Mod in Go returns the integer part instead of the remainder of the floating point

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