Does string replace characters?

Question

Does string replace characters?

I have an object like this:

myDataObject = {
    name : 'Nikola Tesla',
    birth : ['10 July 1856','10. Juli 1856'],
    nation : ['Serbian','Serbisch'],
    knownFor : ['Alternating current',' Zweiphasenwechselstrom']
}

And two string patterns like these:

var englishStr = '#name#, born #birth[1]# , #nation[1]# best known for his contributions to #knownFor[1]#';

var deutschStr = '#name#, geboren #birth[2]#, #nation[2]# Erfinder, der für seine Beiträge zur #knownFor[2]# bekannt';

Now I want to replace #properties#in this way.

I could do it easily if there weren’t a multilingual indicator like [1] or [2]. similar to this:

$.each(myDataObject , function(n, v){
    englishStr = englishStr.replace('#'+ n +'#' , v )
});

So what can I do with #prop[i]#? Thanks you

+3

javascript jquery

user3253797 Feb 04 '14 at 20:46

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5 answers

I suggest you try a slightly different approach. Instead of looping around myDataObjectblindly trying to replace the values, first pull out the values you want to replace, and then replace them with their values.

var regex = /#(.*?)(?:\[(\d*)])?#/g;
while(match = regex.exec(englishStr)){
    var matchStr = match[0];
    var data = myDataObject[match[1]];
    if(match[2] !== undefined){
        data = data[match[2] - 1];
    }

    englishStr = englishStr.replace(matchStr, data);
}

DEMO: http://jsfiddle.net/35jZM/

+1

Rocket Hazmat 04 . '14 21:02

,

$.each(myDataObject , function(n, v){

    if(typeof v == 'object'){
        $.each(v , function(index, value){
            englishStr = englishStr.replace('#'+ n +'[' + index + ']' + '#' , v[index-1]    );

        });
   }
englishStr = englishStr.replace('#'+ n +'#' , v )

});

+1

Mina Gabriel 04 . '14 21:03

, - :

myDataObject = {
    name: 'Nikola Tesla',
    birth: ['10 July 1856', '10. Juli 1856'],
    nation: ['Serbian', 'Serbisch'],
    knownFor: ['Alternating current', ' Zweiphasenwechselstrom']
};

// English: 0, Deutsch: 1
var language = 0;

var str = "#name#, born #$birth# , #$nation# best known for his contributions to  #$knownFor#";

$.each(myDataObject, function (n, v) {
    str = str.replace('#' + n + '#', v);
    str = str.replace('#$' + n + '#', v[language]);
});

alert(str);

Fiddle

+1

Jonathan Feb 04 '14 at 21:04

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You can also pass capture groups to replace the regular expression with a callback function:
^{(note that if arrays in your translation strings are indexed from 1, you need to add this to $2)}

englishStr.replace(/#(.+?)(?:\[(\d+)\])?#/g, function($0, $1, $2){ 
    return $2 === undefined ? myDataObject[$1] : myDataObject[$1][$2];
});

Demo

+1

Emissary Feb 04 '14 at 21:23

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epascarello · Accepted Answer · 2014-02-04T21:05:36+0000

One path would move from a row to a data object, rather than through all keys.

var myDataObject = {
    name : 'Nikola Tesla',
    birth : ['10 July 1856','10. Juli 1856'],
    nation : ['Serbian','Serbisch'],
    knownFor : ['Alternating current',' Zweiphasenwechselstrom']
};
var englishStr = "#name#, born #birth[1]# , #nation[1]# best known for his contributions to  #knownFor[1]#";




var re = /#([^\[#]+)\[?(\d+)?\]?#/;  //Looks for #STRING# or #STRING[NUMBER]#
var test;
while ( (test=re.exec(englishStr))!==null) {  //Keep looking for matches in the string
    var key = test[1];   //get the key to the object
    var index = test[2]; //get the index if there
    var item = myDataObject[key];  //get reference to the item in the object
    if (index!==undefined && item) {  //if we have an index, look up the value from array
        index = parseInt(index,10)-1;  //arrays are zero index, so need to subtract one
        item = item[index];  //get the string
    }
    englishStr = englishStr.replace(re, item || "N/A");  //make the replacement in the string with the data from the object
};

Does string replace characters?

Fiddle

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