As @Zac already pointed out, you can avoid \to avoid the problem. Another way you can find a cleaner 1 is to use string string literals:
string str[]={R"(| | / / ||)",R"(| |/ / ||)", R"(| | ( \ \ \ \`_.)"};
, : ), , , - :
string s = R"!(This (might be) an MS-DOS path\to\a\string)!";
: , : , . . , , , , , . ( ) , - , , , .
1. : ++ 11, , , .