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Breaking a string using brackets using regex in python

Suppose I have a type string str = "[Hi all], [this is] [an example] ". I want to break it down into several parts, each of which consists of contents within a pair. In other words, I want to capture phrases within each pair of brackets. The result should look like this:

['Hi all', 'this is', 'an example']

How can I achieve this using regex in Python?

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2 answers
data = "[Hi all], [this is] [an example] "
import re
print re.findall("\[(.*?)\]", data)    # ['Hi all', 'this is', 'an example']

Regular expression visualization

Demo version of Debuggex

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Try the following:

import re
str = "[Hi all], [this is] [an example] "
contents = re.findall('\[(.*?)\]', str)
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