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Trying to draw a chessboard using a turtle in Python - how can I fill every square?

New to Python, and I'm trying to draw a chessboard. I drew a board, but now I have to define a function (loop) that fills each other square with black. I tried to write a loop to do this for a while, can anyone help?

Here is my code:

import turtle


def drawGrid():
turtle.penup()
turtle.goto(-300, 250)
turtle.pendown()
turtle.forward(300)
turtle.right(90)
turtle.forward(300)
turtle.right(90)
turtle.forward(300)
turtle.right(90)
turtle.forward(300)

def drawColumns():
for i in range(4):
    turtle.right(90)
    turtle.forward(37.5)
    turtle.right(90)
    turtle.forward(300)
    turtle.left(90)
    turtle.forward(37.5)
    turtle.left(90)
    turtle.forward(300)

def drawRows():
turtle.left(180)
rows = 0 
while rows <= 3:
    rows += 1
    turtle.forward(37.5)
    turtle.right(90)
    turtle.forward(300)
    turtle.left(90)
    turtle.forward(37.5)
    turtle.left(90)
    turtle.forward(300)
    turtle.right(90)

def main():
drawGrid()
drawColumns()
drawRows()
if __name__ == "__main__":
main()

Thanks for the help!

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3 answers

The method of filling turtles works on shapes, that is, a completely limited area. Therefore, instead of drawing a grid, you need to think about how to draw a series of squares.

, . , .   

def draw_filled_square(this_turtle, size):    
    """Draw a square by drawing a line and turning through 90 degrees 4 times"""
    this_turtle.pendown()
    this_turtle.fill(True)
    for _ in range(4):
        this_turtle.forward(size)
        this_turtle.right(90)
    this_turtle.fill(False)
    this_turtle.penup()

:

window = turtle.Screen()
myturtle = turtle.Turtle()
square_size = 90
myturtle.goto(-300, 200)

draw__filled_square(myturtle, square_size)

. , , , .

, , , , . .

- , this_turtle.fill(False) .

- (1,2,3,4,1,2,3,4...), modulo (). Modulo , , x y 0, , x y. x% y == 0:

​​ - :

def drum_loop(x):
     # go bang on the fourth beat
     if x % 4 == 0:
         print("bang!")
     else:
         print("tish")

# prints tish, tish, tish, bang! tish, tish, tish, bang!
for i in range(1,9):
   drum_loop(i)

, 0, 1, 0, 1.

, :

for i in range(8): 
    if i % 2 == 0:
        draw_filled_square(myturtle, square_size)
    else:
        draw_unfilled_square(myturtle, square_size)
    # move to start of next square
    myturtle.forward(square_size)

, , modulo 2 .

, , , . ( , ).

+3
import turtle

turtle.pensize(2)
turtle.penup()
turtle.goto(-160,-160)
turtle.pendown()
turtle.color("black")

for i in range(4):
    turtle.forward(320)
    turtle.left(90)

for y in range(-160,160,80):
    for x in range(-160,160,80):
        turtle.begin_fill()
        turtle.penup()
        turtle.goto(x,y)
        turtle.pendown()

        for k in range(4):
            turtle.forward(40)
            turtle.left(90)

        turtle.end_fill()       

for y in range(-120,160,80):
    for x in range(-120,160,80):
        turtle.begin_fill()
        turtle.penup()
        turtle.goto(x,y)
        turtle.pendown()
        for k in range(4):
            turtle.forward(40)
            turtle.left(90)
        turtle.end_fill()   

turtle.done()
0

, , . , , , :

from turtle import Turtle, Screen

NUMBER_SQUARES = 8
SQUARE_SIZE = 40
BOARD_SIZE = SQUARE_SIZE * NUMBER_SQUARES
BORDER_FRACTION = 1.025  # add a slight edge to board

STAMP_SIZE = 20  # size of turtle square image

turtle = Turtle(shape='square', visible=False)
turtle.shapesize(BOARD_SIZE / STAMP_SIZE * BORDER_FRACTION)
turtle.color('black')
turtle.stamp()

turtle.shapesize(SQUARE_SIZE / STAMP_SIZE)
turtle.color('white')
turtle.penup()

for y in range(-NUMBER_SQUARES//2, NUMBER_SQUARES//2):
    parity = y % 2 == 0

    for x in range(-NUMBER_SQUARES//2, NUMBER_SQUARES//2):
        if parity:
            turtle.goto(x * SQUARE_SIZE + SQUARE_SIZE//2, y * SQUARE_SIZE + SQUARE_SIZE//2)
            turtle.stamp()

        parity = not parity

Screen().exitonclick()

This solution can print a board in any two colors (for example, black and red), it does not imply a white background. Another example of a better life through embossing.

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