How to specify a full namespace for factory.create ()

I use suds to make SOAP requests a third-party API.

import suds.client
client = suds.client.Client(WSDL_URL, location=SERVICE_URL)

When I try to create an object for a specific type defined by WSDL (let's say TheObject):

obj = client.factory.create('TheObject')

I get an error message:

(TheObject) not-found
path: "TheObject", not-found
Traceback (most recent call last):
  File "suds_test.py", line 67, in <module>
    sys.exit(main(sys.argv))
  File "suds_test.py", line 51, in main
    obj = client.factory.create('TheObject'),
  File "/usr/local/lib/python2.7/dist-packages/suds/client.py", line 234, in create
    raise TypeNotFound(name)
suds.TypeNotFound: Type not found: 'TheObject'

So, I am printing the list of foam factory types available with print(client):

Suds ( https://fedorahosted.org/suds/ )  version: 0.4 GA  build: R699-20100913

Service ( OrderService ) tns="http://api.example.com/services/"
   Prefixes (2)
      ns0 = "http://api.example.com/contracts/stuff"
      ns1 = "http://api.example.com/services/"
   Ports (2):
      (OrderServiceSoap)
         Methods (123):
            ... Not really relevant
         Types (123):
            SomeType
            SomeType2
            ns0:AnotherType
            ns0:AnotherType2
            ns0:TheObject
            ...

So it seems that ns1is the default namespace, and ns0is the namespace that I want to use for TheObject. If I prefix its namespace alias, it works.

obj = client.factory.create('ns0:TheObject')

ns0 , . Factory.create(), URL- - .

TheObject? URL- ns0 ? .