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Python: method call in map function

map() and a list comprehension is roughly equivalent:

map(function, list1)
[function(i) for i in list1]

What if the function we want to use is a method?

[i.function() for i in list1]
map(.function, list1) # error!
map(run_method(function), list1) # error!

How could I perform such manipulations with map?

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2 answers

Would you use operator.methodcaller():

from operator import methodcaller

map(methodcaller('function'), list1)

methodcaller()accepts additional arguments, which are then passed to the called method; methodcaller('foo', 'bar', spam='eggs')(object)is the equivalent object.foo('bar', spam='eggs').

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map(str.lower, list_of_strings)

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+9

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map(lambda x: type(x).function(), list1)

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map(lambda x: x.function(), list1)

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map(type**function, list1)
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