Extract value between brackets using RegExp

Question

Extract value between brackets using RegExp

I am trying to extract the values between the brackets (and )before I managed to check if the value is there. Help me extract it, please.

Pattern pattern;
         pattern = Pattern.compile("\\b(.*\\b)");
             Matcher matcher = pattern.matcher(node.toString());
             if (matcher.find()){
                System.out.println();// here I need to print value that I find between brackets
             }

+3

java regex

Rudziankoŭ Feb 24 '14 at 21:58

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1 answer

anubhava · Accepted Answer · 2014-02-24T22:00:02+0000

Choose parentheses in your regex:

Pattern pattern = Pattern.compile("\\((.*?)\\)");

Then you can do:

Matcher matcher = pattern.matcher(node.toString());
if (matcher.find()){
    System.out.println( matcher.group(1) );
}

Extract value between brackets using RegExp

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